TABLE III. Group A inspection for device types 03 and 04 - Continued.
Subgroup |
Symbol |
Test no. |
Adapter pin numbers 1/ |
Energized relays |
Measured pin |
Equation 2/ |
Oevice Types |
Limits |
Unit |
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4 |
6 |
7 thru 18 |
22 thru 37 |
No. |
value |
Unit |
Min |
Max |
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1 TA = 25°C |
IFS |
29 |
+15 v |
-15 v |
1111 1111 1111 |
1111 1111 1111 1111 |
K1 |
19 |
I27 |
mA |
IFS = I27 |
03, 04 |
-2.7 |
-1.6 |
mA |
+PSS |
30 31 32 |
+13.5 v +15 v +16.5 v |
" " " |
" " " |
0000 0000 0000 1111 " " |
None " " |
21 " " |
E3 E4 E5 |
v " " |
+PSS = 0.41 (E4 - E3) +PSS = 0.41 (E4 - E5) |
03 " " |
-0.04 " " |
0.04 " " |
LSB/%PS " " |
|
-PSS |
33 34 35 |
+15 v " " |
-13.5 v -15 v -16.5 v |
" " " |
" " " |
" " " |
" " " |
E6 E7 E8 |
" " " |
-PSS = 0.41 (E6 - E7) -PSS = 0.41 (E6 - E8) |
03, 04 " " |
-0.1 " " |
0.1 " " |
" " " |
|
2 TA = 125°C |
vREF |
36 |
+15 v |
-15 v |
0000 0000 0000 |
1111 1111 1111 1111 |
" |
2 |
E9 |
" |
vREF = E9 IREF = 2 mA |
03 |
9.90 |
10.1 |
v |
IZS1 |
37 |
" |
" |
0000 0000 0000 |
1111 1111 1111 1111 |
" |
19 |
I28 |
∝A |
IZS1 = (I28) (4096)/(I56 - I28) |
03, 04 |
-3 |
3 |
LSB |
|
AE |
38 |
" " |
" " |
1111 1111 1111 0000 0000 0000 |
0000 0000 0000 1111 1111 1111 1111 1111 |
" " |
21 " |
E10 E11 |
v " |
AE = 0.1 (E10 - E11) |
03 04 |
-0.50 -0.30 |
0.50 0.30 |
% |
|
BPOE |
39 |
" |
" |
0000 0000 0000 |
1111 1111 1111 1111 |
K2, K3 |
" |
E12 |
" |
BPOE = (-2.05) (E12) |
03 04 |
-20 -12 |
20 12 |
LSB |
|
BZE |
41 |
" |
" |
1000 0000 0000 |
0111 1111 1111 1111 |
K2 |
" |
E14 |
" |
BZE = (-2.05) (E14) |
" |
-10 |
10 |
LSB |
|
LE1 LE15 |
42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 |
" " " " " " " " " " " " " " " |
" " " " " " " " " " " " " " " |
0001 0000 0000 0010 0000 0000 0011 0000 0000 0100 0000 0000 0101 0000 0000 0110 0000 0000 0111 0000 0000 1000 0000 0000 1001 0000 0000 1010 0000 0000 1011 0000 0000 1100 0000 0000 1101 0000 0000 1110 0000 0000 1111 0000 0000 |
1110 1111 1111 1111 1101 " 1100 " 1011 " 1010 " 1001 " 1000 " 0111 " 0110 " 0101 " 0100 " 0011 " 0010 " 0001 " 0000 " |
None " " " " " " " " " " " " " " |
" " " " " " " " " " " " " " " |
E15 E16 E17 E18 E19 E20 E21 E22 E23 E24 E25 E26 E27 E28 E29 |
" " " " " " " " " " " " " " " |
For each input code N calculate the Corresponding linearity error in LSB. LE = 4.1((E10-E11)(N/4095) + E11 -EA) where EA = measured value E15 through E37 N = OUT input digital code word in decimal form Thus for 12 bits N = (A1)(2 exp 11) + (A2) (2 exp 10 )+ … +(A12)(2 exp 0) A1, A2, A12 are 0 or 1. E3 and E4 correspond to the error amplifier Outputs at full scale and zero scale Respectively. |
" " " " " " " " " " " " " " " " " |
-0.5 " " " " " " " " " " " " " " " " |
+0.5 " " " " " " " " " " " " " " " " |
" " " " " " " " " " " " " " " " " |
|
A. Record the OUT code-word, (XXXX 0000 0000), with the most positive error. B. Record the OUT code-word, (YYYY 0000 0000), with the most negative error. |
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See footnotes at end of table.
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