MIL-M-38510-110 Microcircuits, Linear, Quad Operational Amplifiers, Monolithic SiliconThis specification covers the detail requirements for monolithic silicon, quad operational amplifiers. Two product assurance classes and a choice of case outlines and lead finish are provided for each type and are reflected in the complete part number. For this product, the requirements of MIL-M-38510 have been superseded by MIL-PRF-38535, see 6.3.

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Subgroup

Symbol

M1L-STD

-883 method

Test no.

Adapter pin numbers

Energized relays  2/

Measured pins

Equations   3/

Device types

Unit

05

06

Limits

Limits

1

2

3

4

5

No.

Value

Unit

Min

Max

Min

Max

2

TA =+125°C

V1O / T

4001 "

" " " " " " " " " " "

"

25

V1O / T = (V1O (Test 23 - V1O (Test 3)) / 100°C

±30

±30

∝V/°C

11O

26

30 V

GND

-15 V

K5, K6 "

"

"

5 " "

"

E23

V "

"

"

11O = 106 (E19 - E23)/RS

±30

±10

nA "

"

"

27

2 V

-28 V

13 V

E24

11O = 106 (E20 - E24)/ RS

±30

±10

28

5 V

GND

-1.4 V

E25

11O = 106 (E21 - E25)/ RS

±30

±10

29

2.5 V

-2.5 V

1.1 V

E26

11O = 106 (E22 - E26)/ RS

±30

±10

11O/T

30  8/

11O / T = (11O (Test 28 - 11O (Test 7)) / 100°C

±400

±400

pA/°C

+11B

31

30 V

GND

-15 V

K5 "

"

"

5 " " " " " " " "

"

E27

V "

" " " " " " "

"

+11B = 106 (E19 -E27)/ RS

-150

+0.1

-50

+0.1

nA "

"

"

32

2 V

-28 V

13 V

E28

+11B = 106 (E20 -E28)/ RS

-150

+0.1

-50

+0.1

33

5 V

-GND

-1.4 V

E29

+11B = 106 (E21 -E29)/ RS

-150

+0.1

-50

+0.1

34

2.5 V

-2.5 V

1.1 V

E30

+11B = 106 (E22 -E30)/ RS

-150

+0.1

-50

+0.1

-11B

35

30 V

GND

-15 V

K6 "

"

"

E31

-11B = 106 (E31 -E19)/ RS

-150

+0.1

-50

+0.1

nA "

"

"

36

2 V

-28 V

13 V

E32

-11B = 106 (E32 -E20)/ RS

-150

+0.1

-50

+0.1

37

5 V

GND

-1.4 V

E33

-11B = 106 (E33 -E21)/ RS

-150

+0.1

-50

+0.1

38

2.5 V

-2.5 V

1.1 V

E34

-11B = 106 (E34 -E22)/ RS

-150

+0.1

-50

+0.1

+PSRR

4003

"

39

30 V

GND

-1.4 V

None

E35

+PSRR = (E35 - E36)

x 40

±100

±100

∝V/V

"

5 V

GND

-1.4 V

None

E36

CMR

4003

40  4/

Calculate value using data from tests 21 and 22.

CMR = 20 log

4

12.8 x 10   / E19 - E201

76

76

dB

1OS(+)

3011

41  6/

30 V

GND

GND

-25 V

None

3

13

mA

1OS(+) = 13

-70

-70

mA

1CC

3005

42  7/

30 V

GND

None

2

14

mA

1CC = 14

3

3

mA

2

TA =

+125°C

V1O

4001

43  4/

30 V

GND

-15 V

None

" " "

5 " "

"

E37

V "

"

"

V1O = E37

±7

±4

mV "

"

"

44  4/

2 V

-28 V

13

E38

V1O = E38

±7

±4

45  4/

5 V

GND

-1.4 V

E39

V1O = E39

±7

±4

46  4/

2.5 V

-2.5

1.1 V

E40

V1O = E40

±7

±4

V1O / T

47  8/

V1

O / T = (V1O (Test3 - V1O (Test 45)) / 80°C                             

±30

±30

∝V/°C