MIL-M-38510-110 Microcircuits, Linear, Quad Operational Amplifiers, Monolithic SiliconThis specification covers the detail requirements for monolithic silicon, quad operational amplifiers. Two product assurance classes and a choice of case outlines and lead finish are provided for each type and are reflected in the complete part number. For this product, the requirements of MIL-M-38510 have been superseded by MIL-PRF-38535, see 6.3.

Pages 1 - 2 - 3 - 4 - 5 - 6 - 7 - 8 - 9 - 10 - 11 - 12 - 13 - 14 - 15 - 16 - 17 - 18 - 19 - 20 - 21 - 22 - 23 - 24 - 25 - 26 - 27 - 28 - 29 - 30 - 31 - 32 - 33 - 34 - 35 - 36 - 37 - 38 - 39 - 40

Subgroup

Symbol

M1L-STD

-883 method

Test no.

Adapter pin numbers

Energized relays  2/

Measured pins

Equations   3/

Device types

Unit

05

06

Limits

Limits

1

2

3

4

5

No.

Value

Unit

Min

Max

Min

Max

1

TA =

+25°C

V1O

4001

1  4/

30 V

GND

-15 V

None

" " "

5 " " " " " " " " " " " " " " " "

"

E1

V "

" " " " " " " " " " " " " " "

"

V1O = E1

±5

±2

mV "

"

"

2  4/

2 V

-28 V

13 V

E2

V1O = E2

±5

±2

3  4/

5 V

GND

-1.4 V

E3

V1O = E3

±5

±2

4  4/

2.5 V

-2.5 V

1.1 V

E4

V1O = E4

±5

±2

11O

5

30 V

GND

-15 V

K5, K6 "

"

"

E5

11O = 106 (E1 - E5)/RS

±30

±10

nA "

"

"

6

2 V

-28 V

13 V

E6

11O = 106 (E2 - E6) /RS

±30

±10

7

5 V

GND

-1.4 V

E7

11O = 106 (E3 - E7) /RS

±30

±10

8

2.5 V

-2.5 V

1.1 V

E8

11O = 106 (E4 - E8) /RS

±30

±10

+11B

9

30 V

GND

-15 V

K5 "

"

"

E9

+11B = 106 (E1 -E9) /RS

-150

+0.1

-50

+0.1

nA "

"

"

10

2 V

-28 V

13 V

E10

+11B = 106 (E2 -E10) /RS

-150

+0.1

-50

+0.1

11

5 V

GND

-1.4 V

E11

+11B = 106 (E3 -E11) /RS

-150

+0.1

-50

+0.1

12

2.5 V

-2.5 V

1.1 V

E12

+11B = 106 (E4 -E12) /RS

-150

+0.1

-50

+0.1

-11B

13

30 V

GND

-15 V

K6 "

"

"

E13

-11B = 106 (E13 -E1) /RS

-150

+0.1

-50

+0.1

nA "

"

"

14

2 V

-28 V

13 V

E14

-11B = 106 (E14 -E2) /RS

-150

+0.1

-50

+0.1

15

5 V

GND

-1.4 V

E15

-11B = 106 (E15 -E3) /RS

-150

+0.1

-50

+0.1

16

2.5V

-2.5 V

1.1 V

E16

-11B = 106 (E16 -E4) /RS

-150

+0.1

-50

+0.1

+PSRR

4003

17

30 V

GND

-1.4 V

None

E17

+PSRR = (E17 - E18)

x 40

±100

±100

∝V/V

"

5 V

GND

-1.4 V

None

E18

CMR

4003

18  4/

Calculate value using data from tests 1 and 2

CMR = 20 log

4

12.8 x 10   / E1 - E21

76

76

dB

1OS(+)

3011

19  6/

30 V

GND

GND

-25 V

None

3

11

mA

1OS(+) = 11

-70

-70

mA

1CC

3005

20  7/

30 V

GND

None

2

12

mA

1CC = 12

3

3

mA

V1O

4001 "

"

"

21  4/

30 V

GND

-15 V

None

" "

"

5 " "

"

E19

V "

"

"

V1O = E19

±7

±4

mV "

"

"

22  4/

2 V

-28 V

13 V

E20

V1O = E20

±7

±4

2

TA =+125°C

23  4/

5 V

GND

-1.4 V

E21

V1O = E21

±7

±4

24  4/

2.5 V

-2.5 V

1.1 V

E22

V1O = E22

±7

±4