MIL-M-38510-133 Microcircuits, Linear, 10-Bit Digital-To-Analog Converter, Monolithic SiliconThis specification covers the detail requirements for monolithic silicon, 10-bit binary digital-to-analog converters containing deposited thin film resistor networks. Two product assurance classes and a choice of case outlines and lead finishes are provided and are reflected in the complete part number. For this product, the requirements of MIL-M-38510 have been superseded by MIL-PRF-38535, see 6.3

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Subgroup

Symbol

Test no.

Adapter pin numbers

Relays energized

Measured pin

Equation

Limits

Unit

5

6

7 thru 16

22 thru 37

No.

value

Unit

Min

Max

1

TA  = 25°C

8ZE

38

+15 v

-15 v

1000 000 00

1111 1111 1111 1111

None

19

E16

v

8ZE  = E16/(G1)(9.7656E-3)

-2.5

+2.5

LS8

AE1

39

+5 v

"

1111 1111 11

0000 0000 00

0000 0000 0011 1111

1111 1111 1111 1111

"

"

21

E17

E18

"

"

AE1  = 10((E17-E18)/(G1))

-0.5

+0.5

%FS

AE2

40

+15 v

"

1111 1111 11

0000 0000 00

0000 0000 0011 1111

1111 1111 1111 1111

"

"

21

E19

E20

"

"

AE2  = 10((E19-E20)/(G1))

"

"

"

+PSS1

-PSS1

41

42

43

+4.5 v

+5.0 v

+5.5  v

"

" "

1111 1111 11

" "

0000 0000 0011 1111

" "

"

" "

19

" "

E21

E22

E23

"

" "

+PSS1  = ((E21-E22)/G1)(9.7656E-3)(10)

-PSS1  = ((E23-E22)/G1)(9.7656E-3)(10)

-0.01

" "

+0.01

" "

LS8

/%PS "

+PSS2

-PSS2

44

45

46

+13.5 v

+15 v

+16.5 v

"

" "

"

" "

"

" "

"

" "

"

" "

E24

E25

E26

"

" "

+PSS2  = ((E24-E25)/G1)(9.7656E-3)(10)

+PSS2  = ((E26-E25)/G1)(9.7656E-3)(10)

"

" "

"

" "

"

" "

-PSS1

47

48

49

+5 v

" "

-13.5 v

-15 v

-16.5 v

"

" "

"

" "

"

" "

"

" "

E27

E28

E29

"

" "

-PSS1  = ((E27-E28)/G1)(9.7656E-3)(10)

-PSS1  = ((E29-E28)/G1)(9.7656E-3)(10)

-0.025

" "

+0.025

" "

"

" "

-PSS2

50

51

52

+15 v

" "

-10.8 v

-12 v

-13.2 v

"

" "

"

" "

"

" "

"

" "

E30

E31

E32

"

" "

-PSS2  = ((E30-E31)/G1)(9.7656E-3)(10)

-PSS2  = ((E32-E31)/G1)(9.7656E-3)(10)

"

" "

"

" "

"

" "

LE

"

" " " " " " " " " " " " " " " " " " "

53

54

55

56

57

58

59

60

61

62

63

64

65

66

67

68

69

70

71

72

73

"

" "

"

" "

"

" "

"

" "

"

" "

"

" "

"

" "

-15 v

" "

"

" "

"

" "

"

" "

"

" "

"

" "

"

" "

0001 0000 00

0010 0000 00

0011 0000 00

0100 0000 00

0101 0000 00

0110 0000 00

0111 0000 00

1000 0000 00

1001 0000 00

1010 0000 00

1011 0000 00

1100 0000 00

1101 0000 00

1110 0000 00

1111 0000 00

0000 0000 01

0000 0000 10

0000 0001 00

0000 0010 00

0000 0100 00

0000 1000 00

1110 1111 1111 1111

1101 1111 1111 1111

1100 1111 1111 1111

1011 1111 1111 1111

1010 1111 1111 1111

1001 1111 1111 1111

1000 1111 1111 1111

0111 1111 1111 1111

0110 1111 1111 1111

0101 1111 1111 1111

0100 1111 1111 1111

0011 1111 1111 1111

0010 1111 1111 1111

0001 1111 1111 1111

0000 1111 1111 1111

1111 1111 1011 1111

1111 1111 0111 1111

1111 1110 1111 1111

1111 1101 1111 1111

1111 1011 1111 1111

1111 0111 1111 1111

"

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"

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"

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"

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"

" "

"

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"

" "

"

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" "

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" "

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" "

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" "

E33

E34

E35

E36

E37

E38

E39

E40

E41

E42

E43

E44

E45

E46

E47

E48

E49

E50

E51

E52

E53

"

" "

"

" "

"

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"

" "

"

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"

" "

For each input code N calculate the

corresponding linearity error in LS8.

LE  = ((EA/G1)+(N)(K)-(vOS))/(9.7656E-3)

where

EA = measured value E33 through E53

G1 = error amplifier gain from step 28

N = OUT input digital code word in decimal form.  Thus for 10 bits

N = (A1)(2exp7)+(A2)(2exp6)+…

+(A10)(2exp0) A1,A2, … A10 are 0 or 1.

K = actual volts/count scale factor. K = (vFS  - vOS)/1023

where vFS  = value at E19 vOS  = value at E20

-0.5

" "

"

" "

"

" "

"

" "

"

" "

"

" "

"

" "

+0.5

" "

"

" "

"

" "

"

" "

"

" "

"

" "

"

" "

LS8

" "

"

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