MIL-M-38510-125 Microcircuits, Linear, Sample And Hold Circuits, Monolithic SiliconThis specification covers the detail requirements for monolithic silicon, sample and hold circuits. Two product assurance classes and a choice of case outlines and lead finishes are provided and are reflected in the complete part number. For this product, the requirements of MIL-M-38510 have been superseded by MIL-PRF-38535, see 6.4

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Subgroup

Symbol

M1L- STD-

883 method

Test no.

Notes

Adapter pin numbers

Energize d relays

Measured pin

Equation

1/

Limits

Unit

1

2

3

4

5

6

7

No.

value

Units

Min

Max

1

TA =

+25°C

11H

29

30

8/

8.5 v

-21.5 v

Open

5.5 v

0 v

Open

Open

None

4

14

µA

11H = 14

0

10

µA

" " "

"

8.5 v

-21.5 v

"

0 v

5.5 v

"

"

"

5

15

"

11H = 15

0

10

11L

31

32

"

21.5 v

-8.5 v

"

0 v

5.5 v

"

"

"

4

16

"

11L = 16

-1.0

1.0

"

21.5 v

-8.5 v

"

5.5 v

0 v

"

"

"

5

17

"

11L = 17

-1.0

1.0

1OS(+)

3011

33

9/

15 v

-15 v

10 v

2.5 v

0 v

"

"

K1,K2

9

18

mA

1OS(+) = 18             Type 01

Type 02

-25

mA

"

-30

1OS(-)

3011

34

9/

15 v

-15 v

-10 v

2.5 v

0 v

"

"

K1,K2

9

19

"

1OS(-) = 19              Type 01

Type 02

25

mA

"

30

1HL(+)

35

10/

3.5 v

-26.5 v

See fig. 8

timing

�t = 100 ms

-11. 5 v

"

"

None

8

E34

mv

1HL(+) = (E35 - E34)

-100

100

pA

" " "

"

E35

mv

"

"

1HL(-)

36

10/

26.5 v

-3.5 v

11.5 v

"

"

"

"

E36

mv

1HL(-) = (E37 - E36)

"

"

"

E37

mv

"

"

1CH(+)

37

11/

15 v

-15 v

11.5 v

2.5 v

0 v

"

9.5 v

K1,K2,K3

7

110

mA

1CH(+) = 110

-3

mA

1CH(-)

38

11/

"

"

-11.5 v

2.5 v

"

"

-9.5 v

"

"

111

mA

1CH(-) = 111

3

mA

vTH(H)

39

12/

"

"

-2 v

2.0 v

"

"

0 v

"

"

112

mA

vTH(H) ≤ 2 v if 112 � 1 mA

1

mA

vTH(L)

40

12/

"

"

-2 v

0.8 v

"

"

0 v

"

"

113

µA

vTH(L) ≤ 0.5 v if -10 < 113 < 10 µA

-10

10

µA

2

TA =

+125°C

v1O

4001

" " " "

41

42

43

44

45

2/ 3/

" " " "

3.5 v

26.5 v

15 v

7 v

3 v

-26.5 v

-3.5 v

-15 v

-3 v

-7 v

Open

" " " "

-9 v

14 v

2.5 v

4.5 v

0.5 v

-11.5 v

11.5 v

0 v

2 v

-2 v

Open

" " " "

Open

" " " "

None

" " " "

8

" " " "

E38

E39

E40

E41

E42

v

" " " "

v1O = 10 (E38 - E1) v1O = 10 (E39 - E1) v1O = 10 (E40 - E1) v1O = 10 (E41 - E1)

v1O = 10 (E42 - E1)

-5

" " " "

5

" " " "

mv

" " " "

118

4001

" " " "

46

47

48

49

50

3/

" " " "

3.5 v

26.5 v

15 v

7 v

3 v

-26.5 v

-3.5 v

-15 v

-3 v

-7 v

"

" " " "

9 v

14 v

2.5 v

4.5 v

0.5 v

-11.5 v

11.5 v

0 v

2 v

-2 v

"

" " " "

"

" " " "

K1

" " " "

"

" " " "

E43

E44

E45

E46

E47

"

" " " "

118 = 100 (E38 - E43)

118 = 100 (E39 - E44)

118 = 100 (E40 - E45)

118 = 100 (E41 - E46)

118 = 100 (E42 - E47)

-25

" " " "

75

" " " "

nA

" " " "

Z1

51

Calculate value using data from tests 41, 42, 46, and 47.

Z1 = 0.23 / IE38 +E44 -E39 -E43I

1

Gn

AE

52

3.5 v

26.5 v

-26.5 v

-3.5 v

Open

"

-9 v

14 v

-11.5 v

11.5 v

Open

"

Open

"

K4

K4

8

"

E48

E49

v

"

AE = (E48 - E49) / 23

-.02

.02

%

"

53

-02

only

5 v

25 v

-25 v

-5 v

"

"

-7.5 v

12.5 v

-10 v

10 v

"

"

"

"

K7

K7

"

"

E50

E51

"

"

AE = (E50 - E51) / 20

-.02

.02

"

"

54

3 v

7 v

-7 v

-3 v

"

"

0.5 v

4.5 v

-2 v

2 v

"

"

"

"

K4

K4

"

"

E52

E53

"

"

AE = (E52 - E53) / 4

-.04

.04

"

"

v1O

ADJ(+)

55

15 v

-15 v

"

2.5 v

0 v

"

"

K5

"

E54

"

v1O ADJ(+) = 10 (E40 - E54)

6

mv

v1O

ADJ(-)

56

15 v

-15 v

"

2.5 v

0 v

"

"

K8

"

E55

"

v1O ADJ(-) = 10 (E40 - E55)

-6

mv