TABLE lll. Group A inspection for device types 01 and 02.
Subgroup |
Symbol |
Test no. |
Adapter pin numbers |
Energized relays |
Measured pin |
Equations |
Limits |
Unit |
||||||||||||||
Device 01 |
Device 02 |
|||||||||||||||||||||
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
No. |
Value |
Unit |
Min |
Max |
Min |
Max |
||||||
1 TA = 25°C |
MAx-y- |
1 |
---- |
---- |
-10 V |
0 V |
-10 V |
0 V |
---- |
0 V |
-15 V |
+15 V |
11 |
E1 |
V |
MAx-y- = (E1-10)/10 x 100 |
-0.5 |
0.5 |
-1.0 |
1.0 |
%FS |
|
MAx-y+ |
2 |
---- |
---- |
‘’ |
‘’ |
+10 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
E2 |
‘’ |
MAx-y+ = (E2+10)/10 x 100 |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
||
MAx+y- |
3 |
---- |
---- |
+10 V |
‘’ |
-10 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
E3 |
‘’ |
MAx+y- = (E3+10)/10 x 100 |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
||
MAx+y+ |
4 |
---- |
---- |
‘’ |
‘’ |
+10 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
E4 |
‘’ |
MAx+y+ = (E4-10)/10 x 100 |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
||
VOlO |
5 |
---- |
---- |
0 V |
‘’ |
0 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
E5 |
mV |
VOlO = E5 |
-15.0 |
15.0 |
-30.0 |
30.0 |
mV |
||
VlO(x) |
6 |
---- |
---- |
‘’ |
‘’ |
-10 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
E6 |
‘’ |
VlO(x) = (E6-E7)/2 |
-10.0 |
10.0 |
-20.0 |
20.0 |
‘’ |
||
VlO(x) |
7 |
---- |
---- |
‘’ |
‘’ |
+10 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
E7 |
‘’ |
||||||||
VlO(y) |
8 |
---- |
---- |
-10 V |
‘’ |
0 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
E8 |
‘’ |
VlO(y) = (E8-E9)/2 |
‘’ |
‘’ |
‘’ |
‘’ |
" |
||
VlO(y) |
9 |
---- |
---- |
+10 V |
‘’ |
‘’ |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
E9 |
‘’ |
||||||||
VlO(z) |
10 |
---- |
---- |
+1 V |
‘’ |
‘’ |
---- |
0 V |
‘’ |
‘’ |
‘’ |
K10, K12 |
‘’ |
E10 |
‘’ |
VlO(z) = (E10)/10 |
-15.0 |
15.0 |
-30.0 |
30.0 |
" |
|
+llB(x) |
11 |
---- |
---- |
---- |
‘’ |
‘’ |
0 V |
‘’ |
‘’ |
‘’ |
‘’ |
K5 |
14 |
l1 |
µA |
-2.0 |
2.0 |
-2.0 |
2.0 |
µA |
||
+llB(y) |
12 |
---- |
---- |
0 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
K6 |
‘’ |
l2 |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
" |
||
+llB(z) |
13 |
---- |
---- |
‘’ |
‘’ |
0 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
K9, K10, K12 |
15 |
l3 |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
" |
||
-llB(x) |
14 |
---- |
---- |
‘’ |
---- |
‘’ |
‘’ |
0 V |
‘’ |
‘’ |
‘’ |
K2 |
14 |
l4 |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
" |
||
-llB(y) |
15 |
---- |
---- |
‘’ |
0 V |
‘’ |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
K4 |
‘’ |
l5 |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
" |
||
-llB(z) |
16 |
---- |
---- |
‘’ |
‘’ |
‘’ |
0 V |
‘’ |
---- |
‘’ |
‘’ |
K8 |
15 |
l6 |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
" |
||
llO(x) |
17 |
---- |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
0 V |
‘’ |
‘’ |
---- |
---- |
---- |
llO(x) = l1-l4 |
-250.0 |
250.0 |
-250.0 |
250.0 |
nA |
||
llO(y) |
18 |
---- |
---- |
‘’ |
‘’ |
‘’ |
‘’ |
‘’ |
---- |
‘’ |
‘’ |
---- |
---- |
---- |
llO(y) = l2-l5 |
‘’ |
‘’ |
‘’ |
‘’ |
" |
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